**Puzzle:** Four people need to cross a rickety bridge at night. Unfortunately, they have only one torch and the bridge is too dangerous to cross without one. The bridge is only strong enough to support two people at a time. Not all people take the same time to cross the bridge. Times for each person: 1 min, 2 mins, 7 mins and 10 mins. What is the shortest time needed for all four of them to cross the bridge?

**Puzzle Solution:**

It is 17 mins.

1 and 2 go first, then 1 comes back. Then 7 and 10 go and 2 comes back. Then 1 and 2 go again, it makes a total of 17 minutes.

isn’t it 10 mins as the person who takes 10 min to cross, start with torch in hand and with him persons those take 1,2 and 7 mins go one by one.

No sir, that doesn’t necessarily make sense. How will the torch make it back? Whenever two people cross the bridge, they will always take the time of the person who take the longest to cross it since they have to be together and if they don’t, the devil will eat them.

and where is that devil when one of them is returning back all along..?

There should be only two persons…including the person with torch..

10 Mins is enough those 4 persons are cross the bridge.

(10Mins=7Mins+2Mins+1Mins)

17 is not correct as it does not take into consideration time for return back. If 1 & 2 go and 1 come back then it is 3 mins, then 1 & 7 go (additional 7 mins) and 1 come back (add 1 min) then 1 & 10 go so additional 10 mins. Total 21 mins thats lowest

No… 17 is correct answer..

You consider the largest time duration.we want to minimize it not maximize..

1 & 2 Crosses Time –> 2Min

1 return Time –> 1Min

3 & 4 Crosses Time –> 10Min

2 return Time –> 2Min

1 & 2 Cross Time –> 2Min

Total Time –> 17Min

perfect ans

simple and straight nice one thanx!!!

ROFL

Times for each person: A(1 min), B(2 mins), C(7 mins) and D(10 mins.)

A&B > 2 mins

A goes back 7 Mins

A goes back 10 mis

Total: 21mins

And she is from SPIT

10min is only needed ,assuming the range as entire bridge first the one min guy as well as the 10 min guy cross as the 1 min guy crosses he holds torch so others can see d light now there is only 1 person so the 7 minb guy can cross,he completes then can the other 1 min with the 10 min guy so it can take only 10 min

not mentioned that all people standing on same side

assume 2 people standing on one side and 2 on other side

If it is tough to cross without one.. It would be still be tough for the one who returns..

they ve told it is tough to cross without a torch. “it” refers to a torch here.

It is 21mins.

UP: (1,2) goes first. total=2mins.

RETURN: (1) comes back. so total= 2+1=3mins.

UP:(1,7) goes next. so total=3+7=10mins.

RETURN:(1) comes back. so total= 10+1=11mins.

UP:(1,10) goes next. so total= 11+10 =21mins.

take 7 & 10 together for second round

This is the actual question..

Four people need to cross a rickety rope bridge to get back to their camp at night. Unfortunately, they only have one flashlight and it only has enough light left for seventeen minutes. The bridge is too dangerous to cross without a flashlight, and it’s only strong enough to support two people at any given time.

Each of the campers walks at a different speed. One can cross the bridge in 1 minute, another in 2 minutes, the third in 5 minutes, and the slowest camper takes 10 minutes to cross. How can the campers make it across in exactly 17 minutes?

so wts d final ans?? 17 or 21 mns???

MAY I THINK 12 MNTS BCZ 1AND 2 ND PEOPLE GO AND THEN 37AND 10 TH ONE GO WILL RETURN ONE PERSON IN THAT BRIDGE THENH ALL PEOPLE WILL SAFELY REACH THERE

i don’t know if these people above are fools or not. it is explained well above and again they are taking 21 min

the ans is

1 & 2 : 2min

1come back : 1min

10 & 7 : 10min

2 come back: 2min

1 & 2 : 2min

TOTAL 17min

17 is the right answer :-

First 1 and 2 will go – 2 minute.

then 1 come back with torch- 1 minute

then 7 and 10 will go with torch- 10 minutes

then 2 will come back with torch- 2 minutes

then 1 and 2 will go back – 2 minutes

Total :- 2+1+10+2+2 = 17

All four should go at once, Let bridge decide will fall or not *Jako rakhe saiyaan mar sake na koi#

I feel that answer does not suit the frameset of the question. It says a single person cannot cross bridge but while returning a single person is coming back…………..

I like it people challenge it with 10 min. But you have to remember torch has light towards one direction. Hence question to challenge 10min logic starts with, Who holds the torch when 1min guy and 10 min guys starts crossing? in both cases, we some one crossing bridge without torch light at some point.

Agree with me?

Sorry, 10min possible, 7min holds the torch, 10 and 1 cross, when 1 finishes 2 starts crossing , when 2 finish 7 starts crossing , finally 7 and 10 finish crossing together ie 1+2+7 = 10. All depends on good torch

yes bro…thats correct

Required time is 10 mnts only,

First 10min guy & 7min guy starts- Tourch with 10 min guy,

As soon as 7min guy reaches the other end 2 min guy will start (10 min guy is still in bridge with tourch and with 3 min left to finish his task), as soon as the 2min guy crosses (10 min guy still on bridge with 1min left and tourch in hand) 1min guy will start and finishes with the 10min guy. All in one end within 10min. :p

okay

But when 10 min guy reaches at the point which is 3 min away from other side he must be facing his torch in the direction in which he is traveling. so it is not possible to other guys to on come on bridge because they won’t be able to see!!

1 & 2 Crosses Time –> 2Min

1 return Time –> 1Min

3 & 4 Crosses Time –> 10Min

2 return Time –> 2Min

1 & 2 Cross Time –> 2Min

Total Time –> 17Min

nice!!!

I was wondering one thing: if it is dangerous to cross the bridge without one, then how come every time one of the guys is returning from the other end. Mathematics is ok, but unable to conclude this statement..