**Puzzle:**

You’ve got someone working for you for seven days and a gold bar to pay him. The gold bar is segmented into seven connected pieces. You must give them a piece of gold at the end of every day. What and where are the fewest number of cuts to the bar of gold that will allow you to pay him 1/7th each day?

**Puzzle Solution**:

Lets split the chain as,

Day 1: Give A (+1)

Day 2: Get back A, give B (-1, +2)

Day 3: Give A (+1)

Day 4:Get back A and B, give C (-2,-1,+4)

Day 5:Give A (+1)

Day 6:Get back A, give B (-1,+2)

Day 7:Give A (+1)

didn’t understand. can anybody xplain?

if u are not understanding this simple explanation then u are a damn fool.

I understand its very easy… but this reply is so rude

Even I did’nt understood this..?? who made this faltu puzzle :\

Break the bar as shown in the figure i.e. at two places so that you have one single piece, a group of 2 and a group of 4 pieces.

Day 1: Give him the single piece

Day 2: The main point here is that on 2nd day you take back the one gold bar which you gave on Day 1 and give him group of 2 unbroken bars. So you again have one single bar

Day 3: He gives back the single bar which he got in retrun on day 2 from the worker

Day 4: Take 3 coins in return and give the set of 4 unbroken bar. Now he has one single and 2 connected bars.

Day5: Similar to Day 1

we just cut it into 3 part .

at 1st and 3rd position …

at day 1 we give 1 coin

at 2nd we take 1 coin from him and give him 2 coin joind..

now at 3rd day we give him 1coin …

now we have only 4coin left

on 4th day we give all 4 coin and take from him all 1coin and 2 coin…

now other remainig day we give him these 1 and 2 coin

exclusive for “twinkle”

it is simple we know binary representation

decimal binary(b2,b1,b0)

1 1

2 10

3 11

4 100

5 101

6 110

7 111

where b0 = 1 gold coin

b1 = 2 gold coin

b3 = 4 gold coin

and binary(0 represents take it back, 1 represents give it to the worker)

well [email protected] chetan

Stupid puzzle. Puzzle problem does not indicate that worker can return gold pieces. What if worker decides to spend his gold piece on Day 1?

It is a simple puzzle highlighting the fact that all numbers within a series can be formed from the combination of numbers that are power of two like 1,2,4,8,16 etc

When you say all the numbers in the series. What are the numbers you are talking about and what is the series.

superb awesome puzzle

Sorry. But this is a stupid question as indicated above. And i will explain.

Since you can take gold back from the worker. It means he cant spend it. Untill the whole bar has been given to him. Meaning that he only really gets paid when hes got the whole bar at the end of the week. So u are not actually answering the question which say how do you cut the bar in a way that allows you to “pay” him every day.

It didnt say give him. It said pay. And i dont know about you but when i get paid. Aint nobody getting s#*& back.

What happens when he wants to spend some of his payment on the third day?

I thought this was going to involve how to stack the bars and cut multiple pieces at the same time.

2^0+2^1+2^2=7

So 7 can be divided into 1,2,4

This is generalized solution

thanks for this explanation… Its useful