How Much Money He had Initially ?

Puzzle:

One person has some money in his pocket, He visits four temple on the way. As soon as he enters a temple, his money gets double and he offers Rs. 100 in each temple thus his pocket gets empty after he returns from the fourth temple. Now the question is how much money he had initially ?

Solution:

Let’s assume, person starts with Rs x
After 1st temple visit, he is left with Rs (2x-100)
After 2nd temple visit, he is left with Rs (4x-300)
After 3rd temple visit, he is left with Rs (8x-700)
After 4th temple visit, he is left with Rs (16x-1500), which is zero (as he is left with empty pockets)
Hence he started of with x i.e. Rs 1500/16 i.e. Rs 93.75
Answer: Rs 93.75

11 Thoughts on “How Much Money He had Initially ?

  1. Send me daily this type of questions it’s usefull

  2. Srichakradhar Reddy Nagireddy on February 8, 2016 at 4:12 pm said:

    Just cross checking…
    2 * 93.75 = 187.5
    2 * 87.5 = 175
    2 * 75 = 150
    2 * 50 = 100!
    awesome!

  3. kiran kumar patil on May 10, 2016 at 4:08 pm said:

    Let the person have Rs x with him initially.

    When he reached 1st temple his money becomes double that means 2*x or 2x. After he leaves 1st temple remaining amount is 2x-100

    then after leaving 2nd temple he have [2*(2x-100)]-100 = 4x-300

    then after leaving 3rd temple he have [2*(4x-300)]-100 = 8x-700

    then after leaving 4th temple he have [2*(8x-700)]-100 = 16x-1500 which should be equal to 0 since he has nothing at the end

    So 16x-1500=0
    16x=1500
    x=1500/16=93.75

  4. charan on October 1, 2016 at 10:40 am said:

    easy way is , do it from back.
    2(x) – 100 = 0 for fourth temple, so x should be 50.
    so from 3rd temple he came out with 50 rupees.
    2(x) – 100 = 50 for third temple , so x should be 75
    similarly,
    2(x) – 100 = 75 for second temple , so x should be 87.5
    2(x) – 100 = 87.5 for first temple , so x should be 93.75!!!!

  5. Deep bhayani on March 7, 2017 at 8:36 pm said:

    There stand four temples in a row in a holy place. All the four temples have 100 steps climb. A fellow devotee comes to visit the temples. He drops a Re. 1 coin while climbing each of the 100 steps up. Then he offers half of the money he has in his pocket to the god. After that, he again drops Re. 1 coin while climbing down each of the 100 steps of the temple.

    If he repeats the same process at each temple, he is left with no money after climbing down the fourth temple. Can you find out the total money he had with him initially?

  6. Mohit chouhan on April 10, 2017 at 11:52 am said:

    @deep:
    Initially he had 4500/-
    after reaching 1st temple = 2100
    2nd temple = 900
    3rd temple = 300
    last temple = (300-100)-[(300-100/2]-100 = 0

  7. Dipu v p on June 10, 2017 at 10:26 pm said:

    We can also think in reverse order

    Final balance = 0

    4 the temple
    Get back 100 => 0+100 = 100
    Then get into half => 100/2 = 50

    3 rd temple
    Get back 100 => 50+100 = 150
    Then get into half => 150/2 = 75

    2nd temple
    Get back 100 => 75+100 = 175
    Then get into half => 175/2 = 87.5

    1st temple
    Get back 100 => 87.5+100 = 187.5
    Then get into half => 187.5/2 = 93.75

    So initial balance = 93.75

  8. Amar Ajmera on January 2, 2020 at 6:39 pm said:

    The question is how did his money get double???

    His money must have got doubled in business or somewhere else which he wouldnt have expected while going to the temple. But he knew that he would visit 4 temples donating 100/- each so he carried Rs 400/- and by the time he finished all the four temples his pockets were empty. Keep it simple!!!! :-)

  9. Amar Ajmera tu chutya hai

  10. Ajay C Joshi on April 12, 2020 at 2:45 pm said:

    2 * 93.75 = 187.5 -100 = 87.5
    2 * 87.5 = 175 – 100 = 75
    2 * 75 = 150 – 100 = 50
    2 * 50 = 100 -100 = 0

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