Recursive Level Order Traversal of a tree

Level order traversal is also called  breadth first traversal for the tree.

Non-Recursive solution of the problem is – Non-recursive Level Order Traversal

There are basically two functions in this method. One is to print all nodes at a given level (printLevel), and other is to get height of tree and print level wise nodes.

struct node
    int data;
    struct node* left;
    struct node* right;

void printGivenLevel(struct node* root, int level);
int height(struct node* node);
/* Function to print level order traversal a tree*/
void printLevelOrder(struct node* root)
	int h = height(root);
	int i;
	for(i=1; i<=h; i++)
		printLevel(root, i);
/* Print nodes at a given level */
void printLevel(struct node* root, int level)
	if(root == NULL)
	if(level == 1)
		printf("%d ", root->data);
	else if (level > 1)
		printLevel(root->left, level-1);
		printLevel(root->right, level-1);
/* Compute the "height" of a tree */
int height(struct node* node)
   if (node==NULL)
       return 0;
     int lheight = height(node->left);
     int rheight = height(node->right);
     if (lheight > rheight)

Time Complexity: O(n^2) in worst case. For a skewed tree

0 Thoughts on “Recursive Level Order Traversal of a tree

  1. Anonymous on June 3, 2014 at 7:10 pm said:

    why height+1

  2. Abhishek on February 8, 2015 at 7:40 am said:

    Considering the root node. Since the root node is part of both the left and the right subtree.

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