Given a triangle, find the minimum path sum from top to bottom

Given a triangle, find the minimum path sum from top to bottom. Each step you may move to adjacent numbers on the row below.
For example, given the following triangle
[
[2],
[3,4],
[6,5,7],
[4,1,8,3]
]
The minimum path sum from top to bottom is 11 (i.e., 2 + 3 + 5 + 1 = 11).

Solution: (DP)
Declare pathSum array with length of triangle size(). For triangle, the bottom row length is equal to the height of triangle, so use pathSum to hold the bottom row’s value, then from bottom to up, find minimum path

public class Solution {
    public int minimumTotal(List<List<Integer>> triangle) {
        int m = triangle.size(); //number of rows
        if(m==0) return 0;
        int minSum[][] = new int[m][m];
        minSum[0][0] = triangle.get(0).get(0);
    
        for(int i=1; i<m; i++){
           for(int j=0; j<triangle.get(i).size(); j++){
            if(j==0){
                minSum[i][j] =minSum[i-1][j]+triangle.get(i).get(j);
            }else if(j==triangle.get(i).size()-1){
                minSum[i][j] =minSum[i-1][j-1]+triangle.get(i).get(j);
            }
            else{
                minSum[i][j] = triangle.get(i).get(j)+ Math.min(minSum[i-1][j],minSum[i-1][j-1]);
             }
           }
        }
        int res= minSum[m-1][0];
        for(int i=1; i<m;i++){
            if(minSum[m-1][i] < res){
                res = minSum[m-1][i];
            }
        }
        return res;
    }
}