# Write Power Function without using multiplication(*) and division(/) operators

Write your own Power function without using multiplication(*) and division(/) operators?

(Using Nested Loops)

We can calculate power by using repeated addition.

For example to calculate 5^4.
1) First 5 times add 5, we get 25. (5^2)
2) Then 5 times add 25, we get 125. (5^3)
3) Then 5 time add 125, we get 625 (5^4)

Implementation

```/* Works only if a >= 0 and b >= 0  */
int pow(int a, int b)
{
if (b == 0)
return 1;
int increment = a;
int i, j;
for(i = 1; i < b; i++)
{
for(j = 1; j < a; j++)
{
}
}
}
```

Recursive approach of same problem is left for readers to implement.

### 3 Thoughts on “Write Power Function without using multiplication(*) and division(/) operators”

1. Saiteja Turlapati on September 25, 2015 at 4:34 pm said:

#include
#include
int power(int a, int b)
{
int i,sum = 0;
if(b==0) return 1;
for(i=0;i<power(a,b-1);i++)
{
sum += a;
}
return sum;
}

int main()
{
int a,b, sum=0;
printf("Enter a and b\n");
scanf("%d%d",&a,&b);
sum = power(a,b);
printf("POWER=%d",sum);
return 0;
}

2. Uday Pratap Maurya on October 31, 2015 at 11:30 pm said:

int power(int x,int y)
{
if(y==0)

}

3. Uday Pratap Maurya on October 31, 2015 at 11:32 pm said:

int power(int x,int y)
{
if(y==0)
return 1
return x*power(x,y-1);
}