# House Robber | Dynamic Programming

Problem: You have n houses with certain amount of money stashed in each house. You can not steal any adjacent houses. Given a list of non-negative integers representing the amount of money of each house, determine the maximum amount of money you can steal.

Solution:

This is a simple dynamic programming problem. The key is figure out the recurrence relation in the given problem.

At first glance, it appears that the robber could just rob every other house – in which case, we ask whether he should start with the first house or the second house; this could maximize the number of houses he robs. However, it is possible that neither of these possibilities maximize the amount of money he’d steal (e.g. house 1 and 4 have a million dollars each, and the rest have no money).

The recurrence relation for stealing the maximum amount of money is the following:

dp[i] = Math.max(dp[i-1], dp[i-2]+num[i-1])

```public class CrazyForCode {
public int steal(int[] num) {
if(num==null || num.length==0){
return 0;
}
int[] dp= new int[num.length+1];
dp[0]=0;
dp[1]=num[0];
for(int i=2; i<=num.length;i++){
dp[i] =Math.max(dp[i-1],num[i-1]+dp[i-2]);
}
return dp[num.length];
}
}
```

Time Complexity: O(n)

### 4 Thoughts on “House Robber | Dynamic Programming”

1. public class Solution {
public int rob(int[] nums) {
int m1=0;
int m2=0;
if (nums.length == 0) return 0;
if (nums.length == 1) return nums[0];
if (nums.length == 2) return max(nums[0], nums[1]);
m2 = nums[0];
m1 = max(nums[0], nums[1]);
for (int i=2; i n2) return n1;
return n2;
}
}

2. Should the recurrence relation have num[i] instead of num[i-1] ?

3. what would be the output for list [1,25,1,1,24] according to your question also acoording to your logic?